x2 – 4, x2 + 4x + 4 , x3 – 8 বীজগাণিতিক রাশির ল.সা.গু কত?
(x + 2)2 (x3 – 8)
Correct
(x – 2)2 (x3 – 8)
(x2 – 2) (x3 – 8)
(x2 + 2) (x3 – 8)
Explanation:
Correct Answer is: (x + 2)2 (x3 – 8)
১ম রাশি = x2 – 4
= x2 – 22
= (x + 2)(x – 2)
২য় রাশি = x2 + 4x +4
= x2 + 2.x.2 + 22
= (x + 2)2
= (x + 2)(x + 2)
৩য় রাশি = x3 – 8
= x3 – 23
= (x – 2) (x2 + 2.x + 22)
= (x – 2)(x2 + 2x + 4)
নির্ণেয় ল. সা. গু = (x + 2)(x + 2)(x – 2)(x2 + 2x + 4)
=(x + 2)2(x3 – 8)